4x(x-2)=4(x^2-3)-4

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Solution for 4x(x-2)=4(x^2-3)-4 equation: 


Simplifying
4x(x + -2) = 4(x2 + -3) + -4

Reorder the terms:
4x(-2 + x) = 4(x2 + -3) + -4
(-2 * 4x + x * 4x) = 4(x2 + -3) + -4
(-8x + 4x2) = 4(x2 + -3) + -4

Reorder the terms:
-8x + 4x2 = 4(-3 + x2) + -4
-8x + 4x2 = (-3 * 4 + x2 * 4) + -4
-8x + 4x2 = (-12 + 4x2) + -4

Reorder the terms:
-8x + 4x2 = -12 + -4 + 4x2

Combine like terms: -12 + -4 = -16
-8x + 4x2 = -16 + 4x2

Add '-4x2' to each side of the equation.
-8x + 4x2 + -4x2 = -16 + 4x2 + -4x2

Combine like terms: 4x2 + -4x2 = 0
-8x + 0 = -16 + 4x2 + -4x2
-8x = -16 + 4x2 + -4x2

Combine like terms: 4x2 + -4x2 = 0
-8x = -16 + 0
-8x = -16

Solving
-8x = -16

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '-8'.
x = 2

Simplifying
x = 2

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